[plug] Bash "Processing" Script
Jay Turner
jturner at bsis.com.au
Fri Jun 11 12:19:56 WST 2004
> Hi All,
>
> I have written a bash script that I can use to image partitions from one
> disk to another using 'dd'.
>
> As this process can take a while and 'dd' doesn't offer any processing
> information, I was hoping to
> output a '.' to the screen every x seconds while 'dd' does it's thing.
> ie
>
> Imaging............
>
> With a new dot appearing after x seconds.
>
> Does anyone have any ideas on the best way to do this?
As usual, two minutes after I press send, I finally find something after an
hour of searching.
I found the following stop function in Squid's init.d script.
It looks like it can do what I need, I am just having some problems
understanding it..
The portion I think i am interested in I have highlighted for your viewing
pleasure.
Can someone please describe to me the process that occurs here, in
particular, what "while : ;" does.. I think
that might be the key I am looking for.
Thanks
Jay
stop() {
echo -n $"Stopping $prog: "
$SQUID -k check >/dev/null 2>&1
RETVAL=$?
if [ $RETVAL -eq 0 ] ; then
$SQUID -k shutdown &
rm -f /var/lock/subsys/$SQUID
========= Start here ============
timeout=0
while : ; do
[ -f /var/run/squid.pid ] || break
if [ $timeout -ge $SQUID_SHUTDOWN_TIMEOUT ]; then
echo
return 1
fi
sleep 2 && echo -n "."
timeout=$((timeout+2))
done
========== End here? ===========
echo_success
echo
else
echo_failure
echo
fi
return $RETVAL
}
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